Question
The population of a town in 2019 was (x + 5500). It
increased by 25% in the first year and by 20% in the second year. The population in 2021 became (x + 11500). Find the population of the town if instead it had increased by 30% in the first year and then decreased by 20% in the second year.Solution
ATQ, (x + 5500) * 125/100 * 120/100 = x + 11500 (x + 5500) * 1.5 = x + 11500 1.5x + 8250 = x + 11500 1.5x ā x = 11500 ā 8250 0.5x = 3250 x = 6500 Initial population in 2019 = x + 5500 = 6500 + 5500 = 12000 Now, if population had increased by 30% in the first year and decreased by 20% in the second year: New population = (6500 + 5500) * 130/100 * 80/100 = 12000 * 1.3 * 0.8 = 12000 * 1.04 = 12480 So, the new population of the town = 12480
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