Question
The sum of two numbers, x and y, is 640. If x is reduced by
8% and y is raised by 12%, the two values become equal. Determine the value of y.Solution
ATQ,
x + y = 640 ……(i)
ATQ,
0.92 × x = 1.12 × y
Or, x = (1.12/0.92) × y
So, x = (28y/23)
Put the value of ‘x’ in equation (i), we get,
(28y/23) + y = 640
Or, (51y/23) = 640
Or, y = 640 × (23/51)
So, y = 288
45.45 × 11.67 + 14399.88 ÷ 8.01 + 124.79 = ?
(48/16)2 × 50/50 ÷ 50/800 = ? Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(1177.99 + 226.99 + 94.923) ÷ 24.97% of 59.989 = ?
1459.98 ÷ 40.48 × 12.12 = ? × 3.16
(44.85% of 639.79 + 3/8 of 480.23) × (√63.84 – 19.99% of 499.71) = ?
33.02% of (143.92 + 7 × ?) + 34.03 = 99.88
2550.03 ÷ 74.98 x 49.9 = ? + 20.32