Question
The sum of two numbers, x and y, is 640. If x is reduced by
8% and y is raised by 12%, the two values become equal. Determine the value of y.Solution
ATQ,
x + y = 640 ……(i)
ATQ,
0.92 × x = 1.12 × y
Or, x = (1.12/0.92) × y
So, x = (28y/23)
Put the value of ‘x’ in equation (i), we get,
(28y/23) + y = 640
Or, (51y/23) = 640
Or, y = 640 × (23/51)
So, y = 288
1500 × 60% of 25% = ? 2
What will come in the place of question mark (?) in the given expression?
{122 + (66/4) + (252/8)} ÷ 8 = (?)1/2
2 X 25 + (30% of 80) ÷ (10% of 120) = ?
289 + 896 + 144 – 25% of 1100 =?
Find the value of the expression:
18 + 12 – 4 × [22 + 6 – 2 × (38 – 23)]{640 of 8 - (12)2 of 6} - 900 = ?
What will come in place of (?) in the given expression.
√625 + 12 × 5 = ?666(2/3)% of 30 - 116(2/3)% of 90 =?
What will come in the place of question mark (?) in the given expression?
40% of 150 - ?% of 75 = 15 × 1.6
6 × 5.5 + 4.5 × 20 - 102 = ?
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