Question
‘X’ has 40% less sugar than ‘Y’. ‘Y’ has 10%
more sugar than ‘Z’. By what approximate percent is the sugar with ‘X’ less than that with ‘Z’?Solution
ATQ,
Let the sugar with ‘Y’ be ‘10x’.
Sugar with ‘X’ = 0.60 × 10x = ‘6x’
Sugar with ‘Z’ = (10x / 1.10) = ‘9.09x’
Required percentage = {(9.09x – 6x)/9.09x} × 100 ≈ 33.99% or 34%
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