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    Question

    ‘X’ has 40% less sugar than ‘Y’. ‘Y’ has 10%

    more sugar than ‘Z’. By what approximate percent is the sugar with ‘X’ less than that with ‘Z’?
    A 12% Correct Answer Incorrect Answer
    B 60% Correct Answer Incorrect Answer
    C 34% Correct Answer Incorrect Answer
    D 8% Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the sugar with ‘Y’ be ‘10x’.

    Sugar with ‘X’ = 0.60 × 10x = ‘6x’

    Sugar with ‘Z’ = (10x / 1.10) = ‘9.09x’

    Required percentage = {(9.09x – 6x)/9.09x} × 100 ≈ 33.99% or 34%

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