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      Question

      ‘X’ has 40% less sugar than ‘Y’. ‘Y’ has 10%

      more sugar than ‘Z’. By what approximate percent is the sugar with ‘X’ less than that with ‘Z’?
      A 12% Correct Answer Incorrect Answer
      B 60% Correct Answer Incorrect Answer
      C 34% Correct Answer Incorrect Answer
      D 8% Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let the sugar with ‘Y’ be ‘10x’.

      Sugar with ‘X’ = 0.60 × 10x = ‘6x’

      Sugar with ‘Z’ = (10x / 1.10) = ‘9.09x’

      Required percentage = {(9.09x – 6x)/9.09x} × 100 ≈ 33.99% or 34%

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