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    Question

    The sum of the incomes of A and B is Rs. 64,000. A

    spends 50% of his income while B spends 80% of his income such that the savings of B is Rs. 4,000 less than that of A. If the income of C is 10% more than average savings of A and B together, then find the savings of C, given that C saves 40% of his income.
    A Rs. 3,200 Correct Answer Incorrect Answer
    B Rs. 3,600 Correct Answer Incorrect Answer
    C Rs. 4,000 Correct Answer Incorrect Answer
    D Rs. 4,400 Correct Answer Incorrect Answer
    E Rs. 4,800 Correct Answer Incorrect Answer

    Solution

    Let the income of B be Rs. ‘x’ Therefore, income of A = Rs. (64000 – x) Savings of A = 0.5 × (64000 – x) = Rs. (32000 – 0.5x) Savings of B = Rs. 0.2x According to the question, 32000 – 0.5x = 0.2x + 4000 Or, 0.7x = 28000 Or, x = 40000 Savings of A = 32000 – 20000 = Rs. 12000 Savings of B = 8000 Income of C = 1.1 × {(12000 + 8000)/2}
    = 1.1 × 10000
    = Rs. 11000 Savings of C = 0.4 × 11000 = Rs. 4400

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