The total strength of school A is 60% more than that of school B. In school A and B, out of total number of students, 10% and 20% respectively are girls. The number of boys in school A is how much percent more/less than that in school B?
Let the total number of students in school B be ‘x’. Therefore, total number of students in school A = 1.6x Number of boys in school A = 0.90 × 1.6x = 1.44x Number of boys in school B = 0.8x Required % = [(1.44x – 0.8x)/0.8x] × 100 = 80%
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