A and B together have total of Rs.5000 out of which they donated 10% to the orphanage school. The remaining amount is to be then redistributed between them in such a manner that A gets 40% more amount than B. If the amount received by A is Rs.3X, then find the value of [(X/5) + 10].
Let the amount received by B be Rs.P. Therefore, amount received by A = 1.40 x P = Rs.1.4P According to the question, => (P + 1.4P) = 5000 x 0.90 => 2.4P = 4500 => P = 1875 Share of A = 4500 – 1875 = Rs.2625 So, 3X = 2625 => X = 875 Required value = [(X/5) + 10] = 175 + 10 = 185
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