Question
A and B together have total of Rs.5000 out of which they
donated 10% to the orphanage school. The remaining amount is to be then redistributed between them in such a manner that A gets 40% more amount than B. If the amount received by A is Rs.3X, then find the value of [(X/5) + 10].Solution
Let the amount received by B be Rs.P. Therefore, amount received by A = 1.40 x P = Rs.1.4P According to the question, => (P + 1.4P) = 5000 x 0.90 => 2.4P = 4500 => P = 1875 Share of A = 4500 – 1875 = Rs.2625 So, 3X = 2625 => X = 875 Required value = [(X/5) + 10] = 175 + 10 = 185
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
I. 2y2 - 15y + 18 = 0
II. 2x2 + 9x - 18 = 0
I. 165x² + 97x + 10 = 0
II. 117y² - 163y + 56 = 0
I. x2 – 19x + 88 = 0
II. (y + 4)2 = 121
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 27x² - 114x + 99 = 0
Equation 2: 18y² - 70y + 68 = 0
I. 8x² - 78x + 169 = 0
II. 20y² - 117y + 169 = 0
I. x ² + 5 x + 6 = 0                Â
II. y²+ 7 y + 12= 0
...I. x2-2x- √5x+2√5 = 0
II. y2-√3 y- √2 y+ √6 = 0
...I. 5x² -14x + 8 = 0 Â
II. 2y² + 17y + 36 = 0  Â
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 41x + 400 = 0
Equation 2: y² - 41y + 420 = 0
Relevant for Exams:
