Question
The marks obtained by A is 25% more than B, and the
marks obtained by C is 155 more than the difference of the marks obtained by A and B. If C obtained 220 marks, then find the marks obtained by A.Solution
Let the marks obtained by B be ‘x’. So, marks obtained by A = 1.25x According to question, (1.25x – x) + 155 = 220 0.25x = 220 - 155 0.25x = 65 x = 65/0.25 x = 260 Therefore, marks obtained by A = 1.25 × 260 = 325 marks
- Suppose both the roots of q² + kq + 49 = 0 are real and equal, then determine the value of 'k'.
I. 84x² - 167x - 55 = 0
II. 247y² + 210y + 27 = 0
l). 2p² + 12p + 18 = 0
ll). 3q² + 13q + 12 = 0
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
I. 6x2 - 47x + 77 =0
II. 6y2 - 35y + 49 = 0
I. 12a2 – 55a + 63 = 0
II. 8b2 - 50 b + 77 = 0
...I. 2y2 – 19y + 35 = 0
II. 4x2 – 16x + 15 = 0
I. 5x² - 24 x + 28 = 0
II. 4y² - 8 y - 12= 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x2 – ...
I.8(x+3)+ 8(-x)=72
II. 5(y+5)+ 5(-x)=150