Question
Seven years ago, the ratio of the ages of A and B was 4:
5. Eight years hence, the ratio of the ages of A and B will be 9:10. What is the sum of their present ages in years?Solution
Seven years ago the ratio of ages of A and B = 4x : 5x Ratio of Present ages of A and B = 4x + 7 : 5x + 7 After 8 years the ratio of ages of A and B, ⇒ (4x + 7 + 8) : (5x + 7 + 8) = 9 : 10 ⇒ 40x + 150 = 45x + 135 ⇒ 5x = 15 ⇒ x = 3 Sum of present ages of A and B = (4 × 3 + 7) + (5 × 3 + 7) = 41 years ∴ The sum of present ages of A and B is 41 years.
I. 49y2 + 35y + 6 = 0
II. 12x2 + 17 x + 6 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
I. √(17x) + √51 = 0  Â
II. √(4y) + 3 = 0
I. 4 x ² - 4 x + 1 = 0                              Â
II. 4 y ² + 4 y  + 1 = 0
...I. 64x2 - 64x + 15 Â = 0 Â Â Â Â
II. 21y2 - 13y + 2Â =0
I. 2y2 - 15y + 18 = 0
II. 2x2 + 9x - 18 = 0
I. 3q² -29q +18 = 0
II. 9p² - 4 = 0
I: 3x² - 18x + 24 = 0
II: 5y² + 10y - 15 = 0
(i) 2x² + 14x - 16 = 0
(ii) y² – y – 12 = 0
The following question contains two equations as I and II.You have to solve both equations and determine the relationship between them.
I). 2a²...
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