Question
What is the least positive number which leaves
remainders 5, 7, and 8 when divided by 6, 8, and 9 respectively?Solution
Let the number be x Given: x ≡ 5 (mod 6) x ≡ 7 (mod 8) x ≡ 8 (mod 9) This means x + 1 is divisible by 6, 8, and 9. LCM of 6, 8, and 9 = 72 So, x + 1 = 72 x = 71
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