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    Question

    The natural numbers 'P', 'Q', and

    'R' satisfy the ratios P:Q = 2:3 and Q:R = 5:4. Which of the following could be a possible value of (6P + 2Q + 4R)?
    A 632 Correct Answer Incorrect Answer
    B 925 Correct Answer Incorrect Answer
    C 723 Correct Answer Incorrect Answer
    D 690 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ, Let тАШQтАЩ = тАШ15aтАЩ So, тАШPтАЩ = 15a ├Ч (2/3) = тАШ10aтАЩ And, тАШRтАЩ = 15a ├Ч (4/5) = тАШ12aтАЩ Since, 6P + 2Q + 4R = 6 ├Ч 10a + 2 ├Ч 15a + 4 ├Ч 12a = 138a Out of the given options only 690 is a multiple of 138.

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