Question
The natural numbers 'P', 'Q', and
'R' satisfy the ratios P:Q = 2:3 and Q:R = 5:4. Which of the following could be a possible value of (6P + 2Q + 4R)?Solution
ATQ, Let ‘Q’ = ‘15a’ So, ‘P’ = 15a × (2/3) = ‘10a’ And, ‘R’ = 15a × (4/5) = ‘12a’ Since, 6P + 2Q + 4R = 6 × 10a + 2 × 15a + 4 × 12a = 138a Out of the given options only 690 is a multiple of 138.
- 'N' is the largest three-digit number that leaves 4 as a remainder when divided by 8, 14 and 10. Find the sum of digits of 'N'.
Some chocolates were distributed among (x + 4) students such that each student received 12 chocolates. If there had been 8 students more, then chocolate...
- The divisor is 60% of the quotient and 6 times the remainder. If the remainder is 1, then what is the dividend?
When the digits of a two-digit number are interchanged, the new number becomes 8 less than 150% of the original number. If the sum of the digits is 7, f...
Four numbers P, Q, R, S satisfy: Q is 25% less than P, Q:R = 9:10, and R:S = 5:8. If the average of P, Q, R, S is 94, find (S – P).
When a number is increased by 60% then the number obtained is 28 less than thrice the original number. Find the original number.
Sum of seven consecutive natural numbers is always divisible by which of the following number?
What is the largest number that when divides 85 and 121 leaves remainders 5 and 11 respectively?
The mean of 12 numbers is 15. When two additional numbers, x and y , are included, the average increases by 1. Given that the difference between x and y...
Consider the following statementÂ
1.There is a finite number of rational numbers between any two rational numbers.
2. There is an infin...
Relevant for Exams:
