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    Question

    What is the least number which can be divided by 10, 25,

    and 40 without leaving any remainder?
    A 200 Correct Answer Incorrect Answer
    B 260 Correct Answer Incorrect Answer
    C 288 Correct Answer Incorrect Answer
    D 220 Correct Answer Incorrect Answer

    Solution

    ATQ,

    We know, the smallest number which can be divisible by 'a', 'b', and 'c' =
    LCM of 'a', 'b', and 'c'.

    Here, 'a', 'b', and 'c' are three different numbers.

    Required number = LCM of 10, 25, 40 = 200

    Therefore, the smallest number which is divisible by 10, 25, and 40 is 200.

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