Question
What is the least number which can be divided by 10, 25,
and 40 without leaving any remainder?Solution
ATQ,
We know, the smallest number which can be divisible by 'a', 'b', and 'c' =
LCM of 'a', 'b', and 'c'.
Here, 'a', 'b', and 'c' are three different numbers.
Required number = LCM of 10, 25, 40 = 200
Therefore, the smallest number which is divisible by 10, 25, and 40 is 200.
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