📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    Question

    Find the difference between minimum and maximum value of

    'k' such that '6k8194' is always divisible by 3.
    A 7 Correct Answer Incorrect Answer
    B 9 Correct Answer Incorrect Answer
    C 6 Correct Answer Incorrect Answer
    D 8 Correct Answer Incorrect Answer

    Solution

    A number is divisible by 3 when the sum of its digits is divisible by 3.
    Sum of digits of '6k8194' = (6 + k + 8 + 1 + 9 + 4) = k + 28.
    So, k + 28 should be divisible by 3.
    Possible values of 'k' = 2, 5, 8
    Minimum value of 'k' = 2
    Maximum value of 'k' = 8
    Required difference = 8 – 2 = 6

    Practice Next
    More No. System Questions

    Relevant for Exams:

    ask-question