ЁЯУв Too many exams? DonтАЩt know which one suits you best? Book Your Free Expert ЁЯСЙ call Now!

    Question

    Find the difference between minimum and maximum value of

    'k' such that '6k8194' is always divisible by 3.
    A 7 Correct Answer Incorrect Answer
    B 9 Correct Answer Incorrect Answer
    C 6 Correct Answer Incorrect Answer
    D 8 Correct Answer Incorrect Answer

    Solution

    A number is divisible by 3 when the sum of its digits is divisible by 3.
    Sum of digits of '6k8194' = (6 + k + 8 + 1 + 9 + 4) = k + 28.
    So, k + 28 should be divisible by 3.
    Possible values of 'k' = 2, 5, 8
    Minimum value of 'k' = 2
    Maximum value of 'k' = 8
    Required difference = 8 тАУ 2 = 6

    Practice Next
    More No. System Questions

    Relevant for Exams:

    ask-question