Question
There are nine consecutive even numbers such that the
smallest number is 20% less than the largest number. Find the sum of the second lowest and second highest numbers.Solution
ATQ, Let the consecutive even numbers be: x, x + 2, x + 4, x + 6, x + 8, x + 10, x + 12, x + 14, x + 16 According to question: x = 0.80 × (x + 16) 0.20x = 12.8 x = 64 So, the required sum = (x + 2) + (x + 14) = 64 + 2 + 64 + 14 = 144
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