Question
Sum of three positive numbers is 144. If the ratio of
the first and second number is 3:5, respectively while difference between the first and third number is equal to the second number, then find the third number.Solution
Let the first number be '3x' So, second number = 3x × (5/3) = '5x' And, third number = 3x + 5x = '8x' ATQ: 3x + 5x + 8x = 144 Or, 16x = 144 So, x = 9 So, third number = 8 × 9 = 72
If (x2 + y2) = 9 and (xy)2 = 3, then find the value of (x4 + y4).
If, ( a + b = 20 ) and ( a² + b² = 208 ), then find the value of (a³ + b³).

If (a + b) = 7 and ab = 11, then find the value of (a² + b²).
If (x 2 = 10x – 25), then find the value of [x³ + (x⁴/25)][7 - x³]
If 27 (x+y)³ − 8(x−y)³ = (x + 5y) (Ax² + By² + Cxy), then what is the value of (A+B-C)?
If a + b + c = 8, a² + b² + c² = 18 and ab + b c+ ca = 12, then what is the value of a³ + b³ +c³ –3abc?
- If p = 40 - q - r and pq + r(p + q) = 400, then find the value of (p² + q² + r²).
Find the number of zeroes in 16 × 75 × 40 × 125.
If a + b + c = 6, a³ + b³ + c³-3abc = 342, then what is the value of ab + bc + ca