The average of six consecutive odd numbers is 64, and 'm' is the second largest odd number in that series. The average of six consecutive even numbers is 81, and 'n' is the second smallest even number in that series. If 'm' and 'n' are the first and second term of a series which is in arithmetic progression, then find the 5th term of that arithmetic progression.

If 'm' is the 2nd largest term of the odd series, then the series is (m - 8), (m - 6), (m - 4), (m - 2), m and (m + 2) (m - 8) + (m - 6) + (m - 4) + (m - 2) + m + (m + 2) = 64 × 6 6m - 18 = 384 6m = 402 'm' = 67 If 'n' is the 2nd smallest term of the even series, then the series is (n - 2), n, (n + 2), (n + 4), (n + 6) and (n + 8) (n - 2) + n + (n + 2) + (n + 4) + (n + 6) + (n + 8) = 81 × 6 6n + 18 = 486 6n = 468 'n' = 78 In an A.P. series: qᵗʰ term = a + (q - 1)d, where a is the first term, 'q' is the number of terms and d is the difference between two consecutive terms. 'd' = 78 - 67 = 11 'a' = 67 5th term = 67 + (5 - 1) × 11 = 67 + 44 = 111