Question
When a number is divided by 29, the remainder obtained is
22. What is the remainder when five times that number is divided by 29?Solution
ATQ,
Let the number be:
Number = 29D + 22, where D is an integer.
Five times the number = 5 × (29D + 22) = 145D + 110
Now divide by 29:
(145D + 110) = (145D + 87 + 23)
⇒ Remainder = 23
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