Question
Find the least number greater than 200 which leaves
remainder 5 when divided by 12, 15, and 18.Solution
ATQ, Required number N: N ≡ 5 (mod LCM of 12,15,18) LCM(12,15,18) = 22 * 32 * 5 = 180 So N = 180k + 5 For N > 200: k=2 ⇒ N = 360 + 5 = 365 Answer: 365
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