Question
Three numbers are in the ratio 5:7:11. The difference
between (sum of the smallest and the largest) and (sum of the smallest and the middle) is 32. Find the largest number.Solution
ATQ, Let the three numbers be 5x, 7x and 11x respectively. ATQ, (5x + 11x) – (5x + 7x) = 32 Or, 4x = 32 So, x = 8 Therefore, largest number = 11x = 11 × 8 = 88
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