Question
Five times a positive integer is 3 less than twice its
square. Find the integer.Solution
Let the positive integer be x, then 5x + 3 = 2x2 2x2 5x-3=0 2x²-6x+x-3 = 0 2x (x-3) + 1(x - 3) = 0 (2x + 1) (x - 3) = 0 Taking,  (x - 3) = 0 x = 3 So, the positive integer is 3.
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