Question
The sum of the digits of a
two-digit number is 12, and the tens digit is twice the units digit. Determine the HCF of this number and the number formed by reversing its digits.Solution
ATQ, Let the tens and unit digit of the number be 2n and n respectively. According to the question: 2n + n = 12 n = 4 Number = 84 = 1 × 2 2 × 3 × 7 Number obtained after revering its digits = 48 = 1 × 24 * 3 HCF of 84 and 48 = 2 2 × 3 = 12
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