Question
Find the sum of squares of first 8 natural
numbers.Solution
Sum of squares of first 'n' natural numbers = n X (n + 1) X (2n + 1) ÷ 6 Required sum = 8 X (8 + 1) X (2 X 8 + 1) ÷ 6 = 8 X 9 X 17 ÷ 6 = 204
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