Question
(5.53 – 4.07) 2/(4.07 – 3.15)(3.15 –
5.53) + (4.07 – 5.53) 2/(3.15 – 5.53)(5.53 – 4.07) + (3.15 – 5.53) 2/(5.53 – 4.07)(4.07 – 3.15) is simplified toSolution
According to the question, Let a = 5.53 – 4.07, b = 4.07 – 3.15 & c = 3.15 – 5.53 a + b + c = 0 Therefore, a3 + b3 + c3 = 3abc Dividing both sides by “abc”, we get (a3 + b3 + c3)/abc = 3abc/abc a2/bc + b2/ca + c2/ab = 3 Hence, (5.53 – 4.07)2/(4.07 – 3.15)(3.15 – 5.53) + (4.07 – 5.53)2/(3.15 – 5.53)(5.53 – 4.07) + (3.15 – 5.53)2/(5.53 – 4.07)(4.07 – 3.15) = 3
What will come in place of (?) question mark in the given number series.
16, 24, 51, 115, 240, ?
Find the missing number in the given number series.
512, 128, 32, 8, ?, 171, 79, 88, 152, ?, 393
15, 31, 67, 131, ?, 375
1, 26, 75, 156, 277, ?
7 29 61 ? 211 349
...18 29 16 31 ? 33
72, 82, 62, 102, 22, ?
?, 15, 45, 225, 1575, 14175
166 156 136 ? 66 16
