Question
What is the sum of digits of the maximum 3-digit number
that leaves 5 as remainder when divided by 10, 15, and 12?Solution
ATQ,
LCM of (10, 15, and 12) = 60
Largest 3-digit number divisible by 60 = 60 × 16 = 960
So, N = 960 + 5 = 965
Sum of digits of 'N' = 9 + 6 + 5 = 20
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