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    Question

    What is the smallest 5-digit number divisible by 10, 18, 30

    and 45?
    A 10,508 Correct Answer Incorrect Answer
    B 10,000 Correct Answer Incorrect Answer
    C 10,080 Correct Answer Incorrect Answer
    D 10,024 Correct Answer Incorrect Answer

    Solution

    ATQ,

    LCM of 10, 18, 30 and 45 = 90

    Least 5-digit number = 10000

    So, 10000 ÷ 90 = 111.11

    Therefore, we should multiply 112 and 90 to get the required 5-digit number

    So, required number = 10,080

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