Question
What is the smallest 5-digit number divisible by 10, 18, 30
and 45?Solution
ATQ,
LCM of 10, 18, 30 and 45 = 90
Least 5-digit number = 10000
So, 10000 ÷ 90 = 111.11
Therefore, we should multiply 112 and 90 to get the required 5-digit number
So, required number = 10,080
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