Question
Find the sum of all multiples of 9 between 1 and 100
(including both ends if applicable).Solution
First multiple of 9 in this range: 9 Last multiple less than or equal to 100: 99 Sequence: 9, 18, 27, β¦, 99 (AP with a = 9, d = 9) Number of terms n: 99 = 9 + (n β 1) Γ 9 99 β 9 = 9(n β 1) 90 = 9(n β 1) β n β 1 = 10 β n = 11 Sum = n/2 Γ (first + last) = 11/2 Γ (9 + 99) = 11/2 Γ 108 = 11 Γ 54 = 594 Answer: 594.
92% of 1650 + 32Β² = ? + 1504 Γ· 16
What approximate value will come in place of question (?) in the following given expression? You are not expected toΒ calculate the exact value.
...- β81.45 + β225.60 + 49.89% of (520.43 + 22.13% of 131.45) = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
956.41 of 45.06% = ?
39.9% of 1720 + 80.2% of 630 = 89.9% of 1280 + ?
(√845 ×19.932+ √4230 ×14.385)/(√1765 ×4.877 ) = ?
(91.004)2 - (40.003)2 - (52.9)2 = ?
A Sales Executive gets a commission on total sales at 10%. If the sale is exceeded Rs.15,000 he gets an additional commission as a bonus of 5% on the ex...
10.232 + 19.98% of 539.99 = ? Γ 7.99