Question
Find the greatest 4-digit number which is exactly divisible by 12, 15 and 21.
Solution
We need a multiple of LCM(12, 15, 21) that is β€ 9999. Prime factors: 12 = 2Β² Γ 3 15 = 3 Γ 5 21 = 3 Γ 7 LCM = 2Β² Γ 3 Γ 5 Γ 7 = 4 Γ 3 Γ 5 Γ 7 = 420 Greatest 4-digit number = 9999 Check how many 420s fit in 9999: 9999 Γ· 420 β 23.8 Largest integer β€ 23.8 is 23 Required number = 420 Γ 23 = 9660
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