Question
On dividing (5757Β + 57) by 58, the remainder
obtained is βRβ. Find the value of (R β 5).Solution
5757Β + 57 = (5757Β + 1 + 56) = (5757Β + 157Β + 56) (amΒ + bm) is divisible by (a + b) for all odd values of βmβ. So, {(5757Β + 157)/58} will be divisible by 58 (57 + 1) So, required remainder is when 56 is divided by 58, which in turn is 56. So, R = 56 Required value = R β 5 = 56 β 5 = 51
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