Question
The sum of three numbers is 114. On dividing the largest
number by the smallest number, the result is 8, which is 1/3rd of the second largest number. Find the largest number.Solution
ATQ, Let the three numbers be: Largest number = A Second largest number = B Smallest number = C A + B + C = 114 Given, A / C = 8 ⇒ A = 8C Also, 8 = (1/3) × B ⇒ B = 24 Now, A + C = 114 – 24 = 90 Substitute A = 8C: 8C + C = 90 9C = 90 C = 10 So, A = 8C = 8 × 10 = 80 Largest number = 80
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