Question
The total of three numbers, A, B, and C, is 2450. The
second number, B, is 4/7 greater than the first number, A. The third number, C, exceeds A by 375. Determine the value of A.Solution
ATQ;
Let A = x
Then B = x + (4/7)x = 11x/7
C = x + 375
Sum: x + (11x/7) + (x + 375) = 2450
Multiplying by 7: 7x + 11x + 7x + 2625 = 17150
25x = 14525
x = 581
(350/?) = 23 + 33
(630 Γ· 35) Γ 2 + 144 = ? Γ 2
?/4 ÷ 9/? = 15% of 800 + `1(2/3)` × `1(1/5)` × 1/2
236.23-653.23+696.23=?
72 Γ 2 = ? + 104 β 14
36895 - 4256 - 2233 = ?Β
What will come in the place of question mark (?) in the given expression?
3.6 X 15 + 4.5 X 12 = 40% of (? - 50)? = 15% of 2400 + 140% of 4200 β 12 3Β
β121 + β961β β289 =?2
