Question
If three positive numbers are in
the ratio 4:6:5 and the sum of their squares equals 1925, determine the smallest of these three numbers.Solution
ATQ, Let the numbers be ‘4x’, ‘6x’ and ‘5x’ ATQ, 16x2 + 36x2 + 25x2 = 1925 Or, 77x2 = 1925 Or, x2 = 25 So, x = 5 {Since, numbers are positive. So, we may discard x = -5} Therefore, smallest number = 4x = 4 × 5 = 20
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