Question
A number leaves a remainder of 17 when divided by 23.
What will be the remainder when three times that number is divided by 23?Solution
Number = (23A + 17) , where 'A' is constant.
Therefore, required remainder = [3 X (23A + 17) ] ÷ 23
= (69A + 51) ÷ 23 = (69A + 46 + 5) ÷ 23 = 5
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