Question
Find the difference between minimum and maximum value
of 'h' such that '1h9843' is always divisible by 3.Solution
A number is divisible by 3 when the sum of its digits is divisible by 3.
Sum of digits of '1h9843' = (1 + h + 9 + 8 + 4 + 3) = h + 25.
So, h + 25 should be divisible by 3.
Possible values of 'h' = 1, 4, 7
Minimum value of 'h' = 1
Maximum value of 'h' = 7
Required difference = 7 – 1 = 6
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