Question

    Find the difference between minimum and maximum value

    of 'i' such that '8i2470' is always divisible by 3.
    A 7 Correct Answer Incorrect Answer
    B 9 Correct Answer Incorrect Answer
    C 6 Correct Answer Incorrect Answer
    D 8 Correct Answer Incorrect Answer

    Solution

    A number is divisible by 3 when the sum of its digits is divisible by 3.
    Sum of digits of '8i2470' = (8 + i + 2 + 4 + 7 + 0) = i + 21.
    So, i + 21 should be divisible by 3.
    Possible values of 'i' = 0, 3, 6, 9
    Minimum value of 'i' = 0
    Maximum value of 'i' = 9
    Required difference = 9 – 0 = 9

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