Question
Find the smallest 4-digit number which is exactly divisible by 6, 9 and 15.
Solution
LCM of 6, 9, 15: 6 = 2 Γ 3 9 = 3Β² 15 = 3 Γ 5 LCM = 2 Γ 3Β² Γ 5 = 2 Γ 9 Γ 5 = 90 We want the smallest multiple of 90 which is β₯ 1000. 1000 Γ· 90 = 11 remainder 10 Next multiple: 90 Γ 12 = 1080 Answer: 1080
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