New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    The product of three consecutive natural numbers is 46,620.

    What is the sum of these three numbers?
    A 108 Correct Answer Incorrect Answer
    B 96 Correct Answer Incorrect Answer
    C 85 Correct Answer Incorrect Answer
    D 79 Correct Answer Incorrect Answer

    Solution

    Let, the three natural numbers be ‘a’, ‘b’, and ‘c’.

    ATQ, a × b × c = 46620

    46620 = 4 × 5 × 9 × 7 × 37

    One of the numbers is 37, and the other numbers are (5 × 7) and (4 × 9), i.e., 35 and 36

    So, the given three consecutive natural numbers are 35, 36, and 37.

    So, the required sum = 35 + 36 + 37 = 108

    Practice Next

    Relevant for Exams: