Question
The product of three consecutive natural numbers is 46,620.
What is the sum of these three numbers?Solution
Let, the three natural numbers be ‘a’, ‘b’, and ‘c’.
ATQ, a × b × c = 46620
46620 = 4 × 5 × 9 × 7 × 37
One of the numbers is 37, and the other numbers are (5 × 7) and (4 × 9), i.e., 35 and 36
So, the given three consecutive natural numbers are 35, 36, and 37.
So, the required sum = 35 + 36 + 37 = 108
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