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    Question

    The product of three consecutive natural numbers is 46,620.

    What is the sum of these three numbers?
    A 108 Correct Answer Incorrect Answer
    B 96 Correct Answer Incorrect Answer
    C 85 Correct Answer Incorrect Answer
    D 79 Correct Answer Incorrect Answer

    Solution

    Let, the three natural numbers be тАШaтАЩ, тАШbтАЩ, and тАШcтАЩ.

    ATQ, a ├Ч b ├Ч c = 46620

    46620 = 4 ├Ч 5 ├Ч 9 ├Ч 7 ├Ч 37

    One of the numbers is 37, and the other numbers are (5 ├Ч 7) and (4 ├Ч 9), i.e., 35 and 36

    So, the given three consecutive natural numbers are 35, 36, and 37.

    So, the required sum = 35 + 36 + 37 = 108

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