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    Question

    If the number '6k3942' is divisible by 3, then find the

    maximum value of 'k'.
    A 7 Correct Answer Incorrect Answer
    B 9 Correct Answer Incorrect Answer
    C 6 Correct Answer Incorrect Answer
    D 1 Correct Answer Incorrect Answer

    Solution

    ATQ,

    A number is divisible by 3 when the sum of its digits is divisible by 3.

    Sum of digits of '6k3942' = 6 + k + 3 + 9 + 4 + 2 = (k + 24)

    (k + 24) is divisible by 3 when k = 0, 3, 6 or 9

    Therefore, maximum value of 'k' = 9

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