Question
Sum of three positive numbers is 128. If the ratio of
the first and second number is 7:9, respectively while difference between the first and third number is equal to the second number, then find the third number.Solution
Let the first number be '7x' So, second number = 7x × (9/7) = '9x' And, third number = 7x + 9x = '16x' ATQ: 7x + 9x + 16x = 128 Or, 32x = 128 So, x = 4 So, third number = 16 × 4 = 64
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