Question
Aman is forming pairs of two natural numbers, A and B,
such that their product equals 350. He wants to determine how many such pairs exist where A and B are co-prime. How many such pairs can be created? ÂSolution
Co-prime numbers are the ones whose HCF is 1. The possible number of pairs of ‘A’ and ‘B’, such that, ‘A’ and ‘B’ are co-prime = 2k – 1 Where, ‘k’ is the number of prime factors of the product. 350 = 21 × 52 × 71 So, the number of prime factors of 350 = k = 3 So, the possible number of pairs of ‘A’ and ‘B’, such that they are co-prime = 23 – 1 = 22 = 4
`(13.022)^(2)+ (42.93)^(2)-(53.125)^(2)+(192.33xx14.88)=?- (88.44)^(2)- (42.03 xx 23.12)`
(22.9)3 + (30.021)² - (19.11)3 - (44.98)² = ?
(10.013 – 12.04) = ? + 7.98% of 4999.98
? (30.03 - 17.98 × 15.99 ÷ 12.01) = 729.03
60.22 of 349.98% + 419.99 ÷ 14.18 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
16(17/23)Â + 11(15/46)Â - 15(17/25) =? - 19(13/23)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
37.06% of 783.45 + 2125% of 51.89 = ?
