Question
The sum of two numbers is 40 whereas the sum of their
reciprocals is (10/3). Find the square of the product of the two numbers.Solution
ATQ,
Let the two numbers be 'p' and 'q'.
So, p + q = 40
And (1/p) + (1/q) = (10/3)
Or, {(p + q)/(pq)} = (10/3)
Or, pq = (3/10) × 40 = 12
So, required square = 12² = 144
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