Question
The sum of two numbers is 40 whereas the sum of their
reciprocals is (10/3). Find the square of the product of the two numbers.Solution
ATQ,
Let the two numbers be 'p' and 'q'.
So, p + q = 40
And (1/p) + (1/q) = (10/3)
Or, {(p + q)/(pq)} = (10/3)
Or, pq = (3/10) × 40 = 12
So, required square = 12² = 144
More No. System Questions
What will come in the place of question mark (?) in the given expression?
(40/25) X 80 - ? = 45% of 300 - 55√(2670+ √(1141+ √(260- √(1251- √(637+ √1521) ) ) ) ) =?
22% of 560 + 34% of 2160 × 5/12 =? + 16% of 920
√? + √1296 + √729 = 464/4
62.94% of 1800 - 15.03 % of 2400 = ?
464 + 181 +? = (154 × 25) - (15) 2
√1369 + √1024 + √841 =(?)2 − 46
625 × (?% ÷ 125) = 250% of 10
What will come in the place of question mark (?) in the given expression?
9 (? + 12) = 3 (14 + 17 - 11)
(512) (2/3) × √64 ÷ (512) (1/3) = (64) (?/2) ÷ (2)6
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