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    Question

    Find the difference between minimum and maximum value

    of 'b' such that '4b2381' is always divisible by 3.
    A 10 Correct Answer Incorrect Answer
    B 9 Correct Answer Incorrect Answer
    C 8 Correct Answer Incorrect Answer
    D 6 Correct Answer Incorrect Answer

    Solution

    A number is divisible by 3 when the sum of its digits is divisible by 3.
    Sum of digits of '4b2381' = (4 + b + 2 + 3 + 8 + 1) = b + 18.
    So, b + 18 should be divisible by 3.
    Possible values of 'b' = 0, 3, 6, 9
    Minimum value of 'b' = 0
    Maximum value of 'b' = 9
    Required difference = 9 – 0 = 9

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