Question
Find the difference between minimum and maximum value
of 'b' such that '4b2381' is always divisible by 3.Solution
A number is divisible by 3 when the sum of its digits is divisible by 3.
Sum of digits of '4b2381' = (4 + b + 2 + 3 + 8 + 1) = b + 18.
So, b + 18 should be divisible by 3.
Possible values of 'b' = 0, 3, 6, 9
Minimum value of 'b' = 0
Maximum value of 'b' = 9
Required difference = 9 – 0 = 9
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