Question
28% of 50% of 600 = p + 18, find the sum of the squares of
the digits of ‘p’.Solution
ATQ,
28% of 50% of 600 = p + 18
Or, (28/100) × (1/2) × 600 = p + 18
Or, 84 = p + 18
Or, p = 66
Required sum = 6² + 6² = 36 + 36 = 72
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