Question
If the numerator of a fraction is increased by 10% and
the denominator is reduced by 20%, the resulting fraction is 11/6. What was the original fraction?Solution
ATQ,
Let the original fraction be = x/y According to the question: (1.1x)/(0.8y) = 11/6 β 1.1x Γ 6 = 0.8y Γ 11 β 6.6x = 8.8y β x/y = 8.8 / 6.6 β x/y = 88 / 66 β x/y = 4 / 3
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