Question
How many numbers between 200 and 1000 are divisible by both
20 and 30?Solution
ATQ,
A number divisible by both 20 and 30 must be divisible by L.C.M. of 20 and 30 = 60
We look for numbers divisible by 60 in the given range:
First term (a) = 60 × 4 = 240
Common difference (d) = 60
Last term (L) = 60 × 16 = 960
Let the number of terms be n.
Use the A.P. formula:
a + (n - 1)d = L
Substitute values:
240 + (n - 1) × 60 = 960
⇒ 240 + 60n - 60 = 960
⇒ 60n = 780
⇒ n = 780 ÷ 60 = 13
15.63% of 174.99 + √? = 139.98% of 24.98Â
(32.18% of 2399.89 - √624 × 26.25) % of 149.79 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
? = 685.24 + 1024.97 – 9.992 Â
? = 782.24 + 1243.97 – 19.992 Â
20.132 ÷ 62.5% of 11.16 = ? + 5109.21
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
[34.01 × 18.98 – 12 × √576.03 – 198] ÷ 3.95 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
?% of 399.99 + 139.99 ÷ 6.99 = 59.99% of 559.99 + 41.09 X 15.99
