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ATQ,
Let, the number be ‘N’.
ATQ,
N = 391 × k + 34 = 17 × 23 × k + 17 + 17 = 17 × (23 × k + 1) + 17
Since, 17 × (23 × k + 1) is completely divisible by 17
So, if the number is divided by 17, the remainder will be 17.
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