Question
Find the remainder when 345 is divided by 10.
Solution
ATQ, Powers of 3 mod 10 repeat every 4: 31β3, 32β9, 33β7, 34β1 (cycle length 4) 45 Γ· 4 gives remainder 1 (since 45 = 4Γ11 + 1) So remainder = 31 mod 10 = 3
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