Question

    The total of six consecutive even numbers in Set A is

    402. In Set B, the smallest number is 15 less than twice the smallest number in Set A. What is the sum of four consecutive numbers in Set B?
    A 442 Correct Answer Incorrect Answer
    B 440 Correct Answer Incorrect Answer
    C 444 Correct Answer Incorrect Answer
    D 446 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the lowest number of the set A be a
    Therefore,
    a + (a+2) + (a+4) + (a+6) + (a+8) + (a+10) = 402
    6a + 30 = 402
    6a = 372
    a = 62
    Let the lowest number of set B be b
    Therefore, b = 2a - 15 = 2(62) - 15 = 109
    Therefore,
    b + (b+1) + (b+2) + (b+3) = 109 + 110 + 111 + 112 = 442

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