Question
The total of six consecutive even numbers in Set A is
402. In Set B, the smallest number is 15 less than twice the smallest number in Set A. What is the sum of four consecutive numbers in Set B?Solution
Let the lowest number of the set A be a
Therefore,
a + (a+2) + (a+4) + (a+6) + (a+8) + (a+10) = 402
6a + 30 = 402
6a = 372
a = 62
Let the lowest number of set B be b
Therefore, b = 2a - 15 = 2(62) - 15 = 109
Therefore,
b + (b+1) + (b+2) + (b+3) = 109 + 110 + 111 + 112 = 442
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