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    Question

    Find the smallest perfect square that is divisible by 10,

    14, 18, and 21. What is the remainder when it is divided by 85?
    A 12 Correct Answer Incorrect Answer
    B 14 Correct Answer Incorrect Answer
    C 30 Correct Answer Incorrect Answer
    D 27 Correct Answer Incorrect Answer

    Solution

    ATQ,

    LCM of 10, 14, 18 and 21 = 630

    Since, 630 = (2 × 3 × 3 × 5 × 7)

    To make it a perfect square, multiply by (2 × 5 × 7) = 70

    So, required number = 630 × 70 = 44100

    44100 ÷ 85 = 518 × 85 + 30

    So, desired remainder = 30

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