Question
Find the smallest perfect square that is divisible by 10,
14, 18, and 21. What is the remainder when it is divided by 85?Solution
ATQ,
LCM of 10, 14, 18 and 21 = 630
Since, 630 = (2 × 3 × 3 × 5 × 7)
To make it a perfect square, multiply by (2 × 5 × 7) = 70
So, required number = 630 × 70 = 44100
44100 ÷ 85 = 518 × 85 + 30
So, desired remainder = 30
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