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Let the unit and tens digits of the numbers be p and q respectively. Hence, the number = 10q + p According to the question, 1/7 x (10q+p) = 1/2x (10q+p) - 10 5 /14 × (10q+p) = 10 (10q+p) = 28 (10q+p) = 2 x 10 + 8 Hence, p = 8 and q = 2 Thus, (p+q) = 8 + 2 = 10 The sum of the 2-digit number is 10.
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