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    Question

    How many 3-digit numbers are completely divisible by

    5?
    A 175 Correct Answer Incorrect Answer
    B 150 Correct Answer Incorrect Answer
    C 180 Correct Answer Incorrect Answer
    D 165 Correct Answer Incorrect Answer

    Solution

    The first 3 digit that is completely divisible by 5 is 100. The last 3-digit number completely divisible by 5 is 995. Tn= a+ (n − 1) d ⇒ 995 = 100 + (n − 1)5 ⇒ (n − 1) = 895/5 = 179 ⇒ n = 180

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