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    • Question

      How many 3-digit numbers are completely divisible by

      5?
      A 175 Correct Answer Incorrect Answer
      B 150 Correct Answer Incorrect Answer
      C 180 Correct Answer Incorrect Answer
      D 165 Correct Answer Incorrect Answer

      Solution

      The first 3 digit that is completely divisible by 5 is 100. The last 3-digit number completely divisible by 5 is 995. Tn= a+ (n − 1) d ⇒ 995 = 100 + (n − 1)5 ⇒ (n − 1) = 895/5 = 179 ⇒ n = 180

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