Question
How many 3-digit numbers are completely divisible by
5?Solution
The first 3 digit that is completely divisible by 5 is 100. The last 3-digit number completely divisible by 5 is 995. Tn= a+ (n − 1) d ⇒ 995 = 100 + (n − 1)5 ⇒ (n − 1) = 895/5 = 179 ⇒ n = 180
More No. System Questions
? = 20% of 1200 + 256
37% of 810 – 32% of 460.5 = ?
What will come in the place of question mark (?) in the given expression?
(30 × 5 + 20) × 2 = ?
1200 - 60 X 6 + 30 = 30 X 20 + ?
(60 × 8 ÷ 10) × 5 = ?
263 + 1152 - ? + 577 = 1333
? (1/2) = 236 – 25 × 18/2 + 396 ÷ 22
The speed of the stream is 10 km/h. Boat ‘A’ covers 110 km distance against the stream in 11 hours and boat ‘B’ covers 65 km distance against th...
- What will come in the place of question mark (?) in the given expression?
(40 ÷ 5 + 56 ÷ 8) X (? - 42) = 120 2350 – 4830 + 9570 + 3350 – 1720 = ?
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