Question
A mixture contains 72 ml of milk and 36 ml of water. If
27 ml of the mixture is replaced with 18 ml of water, then find the ratio of quantity of milk to that of water in the resultant mixture.Solution
Initial ratio of quantity of milk to that of water = 72:36 = 2:1 Quantity of milk withdrawn = 27 Γ (2/3) = 18 ml Final quantity of milk = 72 β 18 = 54 ml Quantity of water withdrawn = 27 Γ (1/3) = 9 ml Final quantity of water = 36 β 9 + 18 = 45 ml Required ratio = 54:45 = 6:5
Simplify the following expressions and choose the correct option.
{[(13)Β² β (7)Β²] Γ· 12} Γ 4 = ?
(25)Β² Γ 4 Γ· 5 + (3)Β³ + 48=? + 425
?2 + 114 - 48 Γ· 2 Γ 5 = 163
182 + 10 Γ 12 - ? = 312
2/5 of 3/4 of 7/9 of 7200 = ?
If (3 Γ 144 β 252 Γ· 14) Γ· 18 = β1024 β x, then find the value of βxβ.
12.50% of 1440 - 17 × 51 + 721 =?
[(15)³ × (8)²] ÷ (90 × 6) = ?²
?2 - (40% of 240) = 25 X 5
Simplify: 48 Γ· 4 Γ 3 + 5 Γ (6 β 2)